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Linear Combinations and Alternative Coordinate Systems→ VEC-0005/main
Linear Combinations and Alternative Coordinate Systems
How to Read a Coordinate System
Let’s take a fresh look at the familiar rectangular coordinate system. In the diagram on the left, the point \((3,2)\) can be located by
moving your finger 3 units along the \(x\)-axis, then moving your finger 2 units parallel to the \(y\)-axis. We can think of the \(x\) and \(y\) axes
as being determined by the standard unit vectors \(\vec {i}\) and \(\vec {j}\). The vector \(\begin{bmatrix}3\\2\end{bmatrix}\) can be written as a linear combination of \(\vec {i}\) and \(\vec {j}\)
as
Orthogonal unit vectors are often a convenient choice for establishing a coordinate system, but occasionally, using
other vectors is preferrable. An example of an alternative coordinate grid determined by vectors \(\vec {v}_1\) and \(\vec {v}_2\) is shown
below.
Fortunately, finding points and constructing vectors in such coordinate systems relies on the same principles as we use in the
familiear rectangular coordinate system. To reach point \(P\), we first travel 2 units along the line containing \(\vec {v}_1\), then one unit along
the line parallel to \(\vec {v}_2\). We can say that in this coordinate system, \(P\) has coordinates \((2,1)\). Also, observe that vector \(\vec {x}\) can be written as a
linear combination of \(\vec {v}_1\) and \(\vec {v}_2\) as follows
\[\vec {x}=2\vec {v}_1+\vec {v}_2\]
We take it for granted that the \(x\)-coordinate (the coefficient in front of \(\vec {i}\)) is the first component in the ordered pair of coordinates,
and the \(y\)-coordinate (the coefficient in front of \(\vec {j}\)) is the second component.
In the above setup, we chose to list the coefficient in front of \(\vec {v}_1\) as the first coordinate of \(P\) and the coefficient in front of \(\vec {v}_2\) as the
second coordinate.
How would the coordinates of \(P\) be impacted if we had chosen a different order? Think about why establishing (or knowing) the
order in which \(\vec {v}_1\) and \(\vec {v}_2\) are used is important.
The following interactive demonstrates how to find the coordinates for a point using a coordinate grid defined using vectors \(\overrightarrow {OA}\)
and \(\overrightarrow {OB}\) (in that order). To use the interactive, you can either (1) move the sliders to change the coordinates of \(P\) within this
coordinate system, or (2) move the tips of vectors \(\overrightarrow {OA}\) and \(\overrightarrow {OB}\) to change the coordinate system. For (2), explain why the coordinates
of \(P\) do not change while \(P\) moves around the plane.
Explorations
Use the interactive below to answer the questions
List the coordinates for each \(P_i\) with respect to the given coordinate system. Your coordinates should be of the form
\((A\text {-coordinate}, B\text {-coordinate})\).
\[P_1=\left (\answer {1},\answer {1}\right )\]
\[P_2=\left (\answer {-2},\answer {0}\right )\]
\[P_3=\left (\answer {0},\answer {-1}\right )\]
\[P_4=\left (\answer {-2},\answer {3}\right )\]
\[P_5=\left (\answer {3},\answer {-2}\right )\]
Move point \(B\) to coincide with \(P_3\) List the coordinates for each \(P_i\) with respect to the new coordinate system. Your coordinates
should be of the form \((A\text {-coordinate}, B\text {-coordinate})\).
\[P_1=\left (\answer {1},\answer {-1}\right )\]
\[P_2=\left (\answer {-2},\answer {0}\right )\]
\[P_3=\left (\answer {0},\answer {1}\right )\]
\[P_4=\left (\answer {-2},\answer {-3}\right )\]
\[P_5=\left (\answer {3},\answer {2}\right )\]
How do these coordinates compare to the coordinates in the previous question? Explain why this is happening. (Hint: you can
use the RESET button to return to the original coordinate system to compare.)
Press RESET to return to the original coordinate system. Move point \(A\) to coincide with \(P_1\) List the coordinates for each \(P_i\) with
respect to the new coordinate system. Your coordinates should be of the form \((A\text {-coordinate}, B\text {-coordinate})\).
\[P_1=\left (\answer {1},\answer {0}\right )\]
\[P_2=\left (\answer {-2},\answer {2}\right )\]
\[P_3=\left (\answer {0},\answer {-1}\right )\]
\[P_4=\left (\answer {-2},\answer {5}\right )\]
\[P_5=\left (\answer {3},\answer {-5}\right )\]
How do these coordinates compare to the coordinates in the original coordinate system? Explain why this is happening. (Hint:
you can use the reset button to return to the original coordinate system to compare.)
Press RESET to return to the original coordinate system. Express each \(\overrightarrow {OP}_i\) as a linear combination of \(\overrightarrow {OA}\) and
\(\overrightarrow {OB}\).
Discuss the relationship between your answers to the first question and your answers here.
Move point \(B\) to coincide with \(P_2\). What do you observe? Do vectors \(\overrightarrow {OA}\) and \(\overrightarrow {OB}\) determine a good coordinate system for the plane?
Can we express every point in the plane as a linear combination of \(\overrightarrow {OA}\) and \(\overrightarrow {OB}\)? Can we express some points in the plane as linear
combinations of \(\overrightarrow {OA}\) and \(\overrightarrow {OB}\)?
We will use the same set-up as in the previous exploration but introduce an additional vector \(\overrightarrow {OC}\).
Suppose we want to express \(P_1\) using a coordinate system determined by three vectors \(\overrightarrow {OA}\), \(\overrightarrow {OB}\), and \(\overrightarrow {OC}\). If the coordinates are to
be of the form \((A\text {-coordinate}, B\text {-coordinate}, C\text {-coordinate})\), how many ways do you think there would be to express \(P_1\)? Fill in the missing coordinates for \(P_1\)
below.
Based on your work above, express \(\overrightarrow {OP_1}\) as a linear combination of \(\overrightarrow {OA}\), \(\overrightarrow {OB}\), and \(\overrightarrow {OC}\). How many ways do you think there are to do this?
Compare and contrast the coordinate systems in this exploration and Exploration .
Existence and Uniqueness of Representation
What makes a good coordinate system?
Every point has coordinates associated with it;
Coordinates associated with each point are unique.