Suppose \(A\begin{bmatrix}-1\\-1\\2\end{bmatrix}=\begin{bmatrix}0\\1\\1\end{bmatrix}\)
Which of the following can we conclude from the given information? Select ALL that apply.
\(\vec {c}_2+\vec {c}_3=\begin{bmatrix}-1\\-1\\2\end{bmatrix}\) \(-\vec {c}_1-\vec {c}_2+2\vec {c}_3=\begin{bmatrix}0\\1\\1\end{bmatrix}\) \(A\) is non-singular. \(\begin{bmatrix}0\\1\\1\end{bmatrix}\) is in \(\text {span}(\vec {c}_1, \vec {c}_2, \vec {c}_3)\). Vector \(\begin{bmatrix}0\\1\\1\end{bmatrix}\) can be written as a linear combination of the columns of \(A\).