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\(\mbox {null}(A)\) is the orthogonal complement of \(\mbox {row}(A)\), and \(\mbox {null}(A^T)\) is the orthogonal complement of \(\mbox {col}(A)\).
Gram-Schmidt process
An iterative process which constructs an orthogonal basis for a subspace. The idea is to build the
orthogonal set one vector at a time, by taking a vector not in the span of the vectors in the current iteration of the set, and
subtracting its orthogonal projection onto each of those vectors.
Orthogonal Basis
A set of orthogonal vectors that spans a subspace. (Any orthogonal set of vectors must be linearly
independent.)
Orthogonal complement of a subspace
If \(W\) is a subspace, we define the orthogonal complement\(W^\perp \) as the set of all vectors
orthogonal to every vector in \(W\), i.e.,
Let \(W\) be a subspace of \(\RR ^n\) and let \(\vec {x} \in \RR ^n\). Then there exist unique vectors \(\vec {w} \in W\) and \(\vec {w}^\perp \in W^\perp \) such that \(\vec {x} = \vec {w} + \vec {w}^\perp \).
Orthogonal matrices
An \(n \times n\) matrix \(Q\) is called an orthogonal matrix if its columns form an orthonormal set. This will happen if and
only if its rows form an orthonormal set. Note also that \(Q\) is an orthogonal matrix if and only if it is an invertible matrix such that \(Q^{-1}=Q^{T}\).
Orthogonal projection onto a subspace
Let \(W\) be a subspace of \(\RR ^n\) with orthogonal basis \(\{\vec {f}_{1}, \vec {f}_{2}, \dots , \vec {f}_{m}\}\). If \(\vec {x}\) is in \(\RR ^n\), the vector
is called the orthogonal projection of \(\vec {x}\) onto \(W\).
Orthogonal set of vectors
Let \(\{ \vec {v}_1, \vec {v}_2, \cdots , \vec {v}_k \}\) be a set of nonzero vectors in \(\RR ^n\). Then this set is called an orthogonal set if \(\vec {v}_i \dotp \vec {v}_j = 0\) for all \(i \neq j\).
Moreover, if \(\norm {\vec {v}_i}=1\) for \(i=1,\ldots ,m\) (i.e. each vector in the set is a unit vector), we say the set of vectors is an orthonormal set.
Orthogonally diagonalizable matrix
An \(n \times n\) matrix \(A\) is said to be orthogonally diagonalizable if an orthogonal matrix \(Q\) can be found
such that \(Q^{-1}AQ = Q^{T}AQ\) is diagonal.
Orthonormal basis
A set of orthonormal vectors that spans a subspace. (Any orthogonal set of vectors must be linearly
independent by Theorem orthbasis.)
Orthonormal set of vectors
Let \(\{ \vec {v}_1, \vec {v}_2, \cdots , \vec {v}_k \}\) be a set of nonzero vectors in \(\RR ^n\). Then this set is called an orthogonal set if \(\vec {v}_i \dotp \vec {v}_j = 0\) for all \(i \neq j\).
Moreover, if \(\norm {\vec {v}_i}=1\) for \(i=1,\ldots ,m\) (i.e. each vector in the set is a unit vector), we say the set of vectors is an orthonormal set.
Properties of orthogonal matrices
If \(Q\) is an orthogonal matrix, then...
1.
\(Q^{-1} = Q^T\) is orthogonal,
2.
\(\mbox {det} Q = \pm 1\),
3.
if \(\lambda \) is an eigenvalue of \(Q\), then \(|\lambda |=1\),
4.
the product of \(Q\) with any other orthogonal matrix will be an orthogonal matrix (i.e. orthogonal matrices are
closed under matrix multiplication),
and
5.
\(Q\) is a length-preserving and angle-preserving linear transformation.
QR factorization
Let \(A\) be an \(m \times n\) matrix with independent columns. A QR-factorization of \(A\) expresses it as \(A = QR\) where \(Q\)
is \(m \times n\) with orthonormal columns and \(R\) is an invertible and upper triangular matrix with positive diagonal entries.