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Note: the function \(\arctan \) is not actually a function because there are pairs of
angles with the same tangent. To successfully apply the above formulas, double check
that your result coincides with what you actually want to describe. If not, you may
need to replace \(\arctan \) by \(\arctan + \pi \).
1.3 Circles passing through the origin
A circle passing through the origin has equation
\[ (x-a)^2 + (y-b)^2 = c^2 \]
where \((a,b)\) is the center of the circle, \(c\) is
the radius, and \(a^2 + b^2 = c^2\) to guarantee it passes through the origin. Expanding this, we get
\[ x^2 + y^2 - 2 ax - 2 by + a^2 + b^2 = c^2 \]
Cancelling \(a^2 + b^2 = c^2\), and writing \(x\) and \(y\) in terms of \(r \) and \(\theta \), we get
\[ r^2 - 2 a r \cos \theta - 2 b r \sin \theta = 0 \]
Dividing over \(r\), we get
\[ r = 2 a \cos \theta + 2 b \sin \theta \]
Therefore, the description of the interior of the circle in polar coordinates is given by
In rectangular coordinates, a vertical cone with tip at the origin has equation \(z = m \sqrt {x^2 + y^2}\). In
spherical coordinates, this equation becomes
\[ \phi = \arctan ( 1/ m ) \]
The region above the cone is given by
\[ 0 \leq \phi \leq \arctan (1/m) \]
The region below the cone is given by
\[ \arctan (1/m) \leq \phi \leq \pi \]
3.3 Sphere centered in the \(z\)-axis and passsing through the origin
A sphere passing through the origin and centered in the \(z\)-axis has equation
\[ x^2 + y^2 + (z-c)^2 = c^2 \]
Expanding this, we get
\[ x^2 + y^2 + z^2 = 2 c z \]
Putting this in terms of \(\rho \) and \(\phi \), we get
\[ \rho ^2 = 2 c \rho \cos \phi \]
Dividing over \(\rho \), we
get
\[ \rho = 2 c \cos \phi \]
Therefore, the description of the interior of the sphere is
The integrand is \(x^2 + y^2\), which in polar coordinates
becomes \(r^2\). When we pass to polar coordinates, we multiply the integrand
by the Jacobian, which is \(r\). The integral becomes
\begin{gather*} -2 \leq y \leq 2 \\ 0 \leq x \leq \sqrt {4 - y^2 } \\ 0 \leq z \leq x^2 + y^2 \end{gather*}
represent the region above the \(xy\)-plane, below the paraboloid \(z = x^2 + y^2\), on the
side of the \(yz\)-plane with positive \(x\)-coordinate, and inside the cylinder \(x^2 + y^2 = 2\) of radius \(2\). In
cylindrical coordinates, these restrictions become
The integrand is already in terms
of the coordinates \(r,\theta , z\). By passing to cylindrical coordinates, we multiply the
integrand by the Jacobian, which is \(r\). The integral becomes
\begin{gather*} 0 \leq x \leq 2 \\ x \leq y \leq \sqrt {4 - x^2 } \\ \sqrt {3 x^2 + 3 y^2} \leq z \leq \sqrt {16 - x^2 - y^2} \end{gather*}
describe the region..... maybe
it is too difficult to see directly, so first look at the restrictions on \(x\) and \(y\). They
represent the region in the first quadrant above the line \(y = x\) and inside the circle of
radius 2. This means
The restrictions on \(z\) correspond to the region above the cone \(z = \sqrt {3} \sqrt {x^2 + y^2 } \)
and inside the sphere \(x^2 + y^2 + z^2 = 16\). In sphereical coordinates, this becomes
The integrand was \(z (x^2 + y^2) \),
which in spherical coordinates becomes \(\rho ^3 \cos \phi \sin ^2 \phi \). When we pass to spherical coordinates, we
multiply the integrand by the Jacobian, which is \(\rho ^2 \sin \phi \). Then the integral becomes
The integrand in
terms of spherical coordinates becomes \(\rho \cos \phi / \rho ^2 = \cos \phi / \rho \). When we pass to spherical coordinates, we
multiply the integrand by the Jacobian, which is \(\rho ^2 \sin \phi \). Then the integral becomes