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Hints: \(\displaystyle s\mathcal {L}(f(t))-f(0)=\mathcal {L}(f\,^{\prime }(t))=\int _0^{\infty } f^{\,\prime }(t)e^{-st}\,\mathrm {d}t\), and since \(f^{\,\prime }(t)\) is of exponential order \(s_0\), the limit as \(s\rightarrow \infty \) of the improper integral is equal to the improper integral of the limit of the integrand.
Hint: use the result of the previous exercise.