In Exercises sinecosinegraphfirst - sinecosinegraphlast, graph one cycle of the given function. State the period, amplitude, phase shift and vertical shift of the function.
\(f(t) = 3\sin (t)\)

Use the Desmos graph below with the settings \(f(t)=\sin (t),\,h=0,\,b=1,\,a=3,\,k=0\)

Period: \(2\pi \)
Amplitude: \(3\)
Phase Shift: \(0\)
Vertical Shift: \(0\)

\(g(t) = \sin (3t)\)

Use the Desmos graph below with the settings \(f(t)=\sin (t),\,h=0,\,b=3,\,a=1,\,k=0\)

Period: \(\frac {2\pi }{3}\)
Amplitude: \(1\)
Phase Shift: \(0\)
Vertical Shift: \(0\)

\(h(t) = -2\cos (t)\)

Use the Desmos graph below with the settings \(f(t)=\cos (t),\,h=0,\,b=1,\,a=-2,\,k=0\)

Period: \(2\pi \)
Amplitude: \(2\)
Phase Shift: \(0\)
Vertical Shift: \(0\)

\(f(t) = \cos \left ( t - \frac {\pi }{2} \right )\)

Use the Desmos graph below with the settings \(f(t)=\cos (t),\,h=\frac {\pi }{2},\,b=1,\,a=1,\,k=0\)

Period: \(2\pi \)
Amplitude: \(1\)
Phase Shift: \(\frac {\pi }{2}\)
Vertical Shift: \(0\)

\(g(t) = -\sin \left ( t + \frac {\pi }{3} \right )\)

Use the Desmos graph below with the settings \(f(t)=\sin (t),\,h=-\frac {\pi }{3},\,b=1,\,a=-1,\,k=0\)

Period: \(2\pi \)
Amplitude: \(1\)
Phase Shift: \(-\frac {\pi }{3}\)
Vertical Shift: \(0\)

\(h(t) = \sin (2t - \pi )\)

Use the Desmos graph below with the settings \(f(t)=\sin (t),\,h=\pi ,\,b=2,\,a=1,\,k=0\)

Period: \(\pi \)
Amplitude: \(1\)
Phase Shift: \(\frac {\pi }{2}\)
Vertical Shift: \(0\)

\(f(t) = -\frac {1}{3}\cos \left ( \frac {1}{2}t + \frac {\pi }{3} \right )\)

Use the Desmos graph below with the settings \(f(t)=\cos (t),\,h=-\frac {\pi }{3},\,b=\frac {1}{2},\,a=-\frac {1}{3},\,k=0\)

Period: \(4\pi \)
Amplitude: \(\frac {1}{3}\)
Phase Shift: \(-\frac {2\pi }{3}\)
Vertical Shift: \(0\)

\(g(t) = \cos (3t - 2\pi ) + 4\)

Use the Desmos graph below with the settings \(f(t)=\cos (t),\,h=2\pi ,\,b=3,\,a=1,\,k=4\)

Period: \(\frac {2\pi }{3}\)
Amplitude: \(1\)
Phase Shift: \(\frac {2\pi }{3}\)
Vertical Shift: 4

\(h(t) = \sin \left ( -t - \frac {\pi }{4} \right ) - 2\)

Use the Desmos graph below with the settings \(f(t)=\sin (t),\,h=\frac {\pi }{4},\,b=-1,\,a=1,\,k=-2\)

Period: \(2\pi \)
Amplitude: \(1\)
Phase Shift: \(-\frac {\pi }{4}\) (You need to use \(y = -\sin \left ( t + \frac {\pi }{4} \right ) - 2 \) to find this.)
Vertical Shift: \(-2\)

\(f(t) = \frac {2}{3} \cos \left ( \frac {\pi }{2} - 4t \right ) + 1\)

Use the Desmos graph below with the settings \(f(t)=\cos (t),\,h=-\frac {\pi }{2},\,b=-4,\,a=\frac {2}{3},\,k=1\)

Period: \(\frac {\pi }{2}\)
Amplitude: \(\frac {2}{3}\)
Phase Shift: \(\frac {\pi }{8}\) (You need to use\(y = \frac {2}{3} \cos \left ( 4t - \frac {\pi }{2} \right ) + 1\) to find this.)
Vertical Shift: \(1\)

\(g(t) = -\frac {3}{2} \cos \left ( 2t + \frac {\pi }{3} \right ) - \frac {1}{2}\)

Use the Desmos graph below with the settings \(f(t)=\cos (t),\,h=-\frac {\pi }{3},\,b=2,\,a=-\frac {3}{2},\,k=-\frac {1}{2}\)

Period: \(\pi \)
Amplitude: \(\frac {3}{2}\)
Phase Shift: \(-\frac {\pi }{6}\)
Vertical Shift: \(-\frac {1}{2}\)

\(h(t) = 4\sin (-2\pi t + \pi )\)

Use the Desmos graph below with the settings \(f(t)=\sin (t),\,h=-\pi ,\,b=-2\pi ,\,a=4,\,k=0\)

Period: \(1\)
Amplitude: \(4\)
Phase Shift: \(\frac {1}{2}\) (You need to use \(h(t) = -4\sin (2\pi t - \pi )\) to find this.)
Vertical Shift: \(0\)

In Exercises fitsinecosinefirst - fitsinecosinelast, a sinusoid is graphed. Find a formula for the sinusoid in the form \(S(t) = A \sin (\omega t + \phi ) + B\) and \(C(t) = A \cos (\omega t + \phi ) + B\). Select \(\omega \) so \(\omega > 0\).

[Picture]

\(S(t) = 4 \sin \left (t + \frac {\pi }{4} \right )\), \(C(t) = 4 \cos \left (t - \frac {\pi }{4} \right )\)

Use the Desmos graph below to check that both of your formulas agree.

[Picture]

\(S(t) = -3 \sin (t) + 3\), \(C(t) = -3 \cos \left (t - \frac {\pi }{2}\right ) + 3\)

Use the Desmos graph below to check that both of your formulas agree.

[Picture]

\(S(t) = 3 \sin \left ( 2t - \frac {\pi }{3} \right )\), \(C(t) = 3 \cos \left ( 2t - \frac {5\pi }{6} \right )\)

Use the Desmos graph below to check that both of your formulas agree.

[Picture]

\(S(t) = \frac {7}{2} \sin (\pi t) + \frac {1}{2}\), \(C(t) = \frac {7}{2} \cos \left (\pi t \frac {\pi }{2} \right ) + \frac {1}{2}\)

Use the Desmos graph below to check that both of your formulas agree.

Use the graph of \(S(t) = 4 \sin (t)\) to graph each of the following functions. State the period of each.
  1. \(f(t) = | 4 \sin (t)|\)

    Period: \(\pi \)

  2. \(g(t) = \sqrt {4\sin (t)}\)

    Period: \(2\pi \).

In Exercises exploregraphsfirst - exploregraphslast, use a graphing utility to help you and your classmates discuss the given questions.
Graph \(f(t) = \cos (3t) + \sin (t)\). Is this function periodic? If so, what is the period?

\(f(t) = \cos (3t) + \sin (t)\) has period \(2\pi \).
Graph \(f(t) = t \sin (t)\) along with \(y = \pm t\). What do you notice?

The graph of \(f(t) = t \sin (t)\) is bounded by the lines \(y = \pm t\); \(f\) has a variable amplitude of \(t\).
Graph \(f(t) = \frac {\sin (t)}{t}\) along with \(y = \pm \frac {1}{t}\). What do you notice?

The graph of \(f(t) = \frac {\sin (t)}{t}\) is bounded by the graphs of \(y = \pm \frac {1}{t}\); \(f\) has a variable amplitude of \(\frac {1}{t}\).
  1. What appears to be \(\ds {\lim _{t \rightarrow \infty } f(t)}\)? Interpret your answer graphically.

    \(\ds {\lim _{t \rightarrow \infty } f(t) = 0}\). We have a horizontal asymptote \(y = 0\).
  2. Use the Squeeze Theorem, Theorem squeezeth from Section Sequences to prove your claim.

    HINT: Since \(-1 \leq \sin (t) \leq 1\), for \(t>0\), \(-\frac {1}{t} \leq \frac {\sin (t)}{t} \leq \frac {1}{t}\)

    Since \(-\frac {1}{t} \leq \frac {\sin (t)}{t} \leq \frac {1}{t}\), \(\ds {\lim _{t \rightarrow \infty }}\) \(\left (- \frac {1}{t}\right )\) \(=\ds {\lim _{t \rightarrow \infty }}\) \(\frac {1}{t} = 0\), \(\ds {\lim _{t \rightarrow \infty }}\) \(\frac {\sin (t)}{t} = 0\) by the Squeeze Theorem.
Graph \(f(t) = \cos \left (\frac {1}{t}\right )\).
  1. Investigate \(\ds {\lim _{t \rightarrow 0} f(t)}\). Does \(\ds {\lim _{t \rightarrow 0} f(t)}\) exist? Why or why not?

    \(\ds {\lim _{t \rightarrow 0} f(t)}\) does not exist. We have infinitely many oscillations as \(t \rightarrow 0\).
  2. Determine \(\ds {\lim _{t \rightarrow \infty } f(t)}\) and interpret your answer graphically.

    \(\ds {\lim _{t \rightarrow \infty } f(t) = 1}\) since as \(t \rightarrow \infty \), \(\frac {1}{t} \rightarrow 0\). Since cosine is continuous, \(\cos \left (\frac {1}{t}\right ) \rightarrow \cos (0) = 1\). We have a horizontal asymptote \(y = 1\).
Graph \(f(t) = e^{-0.1t} \left ( \cos (2t) + \sin (2t)\right )\) along with \(y = \pm 2 \, e^{-0.1t}\). What do you notice?

The graph of \(f(t) = e^{-0.1t} \left ( \cos (2t) + \sin (2t)\right )\) lies between the graphs of \(y = \pm 2 \, e^{-0.1t}\).
  1. What appears to be \(\ds {\lim _{t \rightarrow \infty } f(t)}\)? Interpret your answer graphically.

    \(\ds {\lim _{t \rightarrow \infty } f(t) = 0}\). We have a horizontal asymptote \(y = 0\).
  2. Use the Squeeze Theorem, Theorem squeezeth from Section Sequences to prove your claim.

    HINT: Since \(-1 \leq \cos (2t) \leq 1\) and \(-1 \leq \sin (2t) \leq 1\), \(-2 \leq \cos (2t) + \sin (2t) \leq 2\). Hence, \(-2 e^{-0.1t} \leq e^{-0.1t} \left ( \cos (2t) + \sin (2t)\right ) \leq 2e^{-0.1t}\)

    Since \(-2 e^{-0.1t} \leq e^{-0.1t} \left ( \cos (2t) + \sin (2t)\right ) \leq 2 e^{-0.1t}\), \(\ds {\lim _{t \rightarrow \infty }}\) \(\left (- 2 e^{-0.1t}\right )\) \( = \ds {\lim _{t \rightarrow \infty }}\) \(2 e^{-0.1t}=0\) , the Squeeze Theorem gives \(\ds {\lim _{t \rightarrow \infty }}\) \( e^{-0.1t} \left ( \cos (2t) + \sin (2t)\right ) = 0\).
Show every constant function \(f\) is periodic by explaining why \(f(x + 117) = f(x)\) for all real numbers \(x\). Then show that \(f\) has no period by showing that you cannot find a smallest number \(p\) such that \(f(x + p) = f(x)\) for all real numbers \(x\).

Said differently, show that \(f(x + p) = f(x)\) for all real numbers \(x\) for ALL values of \(p > 0\), so no smallest value exists to satisfy the definition of ‘period’.

The sounds we hear are made up of mechanical waves. The note ‘A’ above the note ‘middle C’ is a sound wave with ordinary frequency \(f = 440\) Hertz \(= 440 \frac {\text {cycles}}{\text {second}}\). Find a sinusoid which models this note, assuming that the amplitude is \(1\) and the phase shift is \(0\).

\(S(t) = \sin \left (880\pi t\right )\)
The voltage \(V\) in an alternating current source has amplitude \(220 \sqrt {2}\) and ordinary frequency \(f = 60\) Hertz. Find a sinusoid which models this voltage. Assume that the phase is \(0\).

\(V(t) = 220 \sqrt {2} \sin \left (120\pi t\right )\)
The London Eye is a popular tourist attraction in London, England and is one of the largest Ferris Wheels in the world. It has a diameter of 135 meters and makes one revolution (counter-clockwise) every 30 minutes. It is constructed so that the lowest part of the Eye reaches ground level, enabling passengers to simply walk on to, and off of, the ride. Find a sinsuoid which models the height \(h\) of the passenger above the ground in meters \(t\) minutes after they board the Eye at ground level.

\(h(t) = 67.5 \sin \left (\frac {\pi }{15} t - \frac {\pi }{2} \right ) + 67.5\)
On page ?? in Section cosinesinebeyond, we found the \(x\)-coordinate of counter-clockwise motion on a circle of radius \(r\) with angular frequency \(\omega \) to be \(x = r\cos (\omega t)\), where \(t=0\) corresponds to the point \((r,0)\). Suppose we are in the situation of Exercise heightlondoneye above. Find a sinsusoid which models the horizontal displacement \(x\) of the passenger from the center of the Eye in meters \(t\) minutes after they board the Eye. Here we take \(x(t) > 0\) to mean the passenger is to the right of the center, while \(x(t) < 0\) means the passenger is to the left of the center.

\(x(t) = 67.5 \cos \left (\frac {\pi }{15} t - \frac {\pi }{2} \right ) = 67.5 \sin \left (\frac {\pi }{15} t \right )\)
In Exercise yoyotrick in Section RadianMeasure, we introduced the yo-yo trick ‘Around the World’ in which a yo-yo is thrown so it sweeps out a vertical circle. As in that exercise, suppose the yo-yo string is 28 inches and it completes one revolution in 3 seconds. If the closest the yo-yo ever gets to the ground is 2 inches, find a sinsuoid which models the height \(h\) of the yo-yo above the ground in inches \(t\) seconds after it leaves its lowest point.

\(h(t) = 28\sin \left (\frac {2\pi }{3} t - \frac {\pi }{2}\right ) + 30\)
Consider the pendulum below. Ignoring air resistance, the angular displacement of the pendulum from the vertical position, \(\theta \), can be modeled as a sinusoid.

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The amplitude of the sinusoid is the same as the initial angular displacement, \(\theta _0\), of the pendulum and the period of the motion is given by

\[T = 2\pi \sqrt {\frac {\ell }{g}}\]

where \(\ell \) is the length of the pendulum and \(g\) is the acceleration due to gravity.

  1. Find a sinusoid which gives the angular displacement \(\theta \) as a function of time, \(t\). Arrange things so \(\theta (0) = \theta _0\).

    \(\theta (t) = \theta _0 \sin \left (\sqrt {\frac {g}{l}}\, t + \frac {\pi }{2}\right )\)
  2. In Exercise pendulumproblem section RootRadicalFunctions, you found the length of the pendulum needed in Jeff’s antique Seth-Thomas clock to ensure the period of the pendulum is \(\frac {1}{2}\) of a second. Assuming the initial displacement of the pendulum is \(15^{\circ }\), find a sinusoid which models the displacement of the pendulum \(\theta \) as a function of time, \(t\), in seconds.

    \(\theta (t) = \frac {\pi }{12} \sin \left (4\pi t + \frac {\pi }{2}\right )\)
The table below lists the average temperature of Lake Erie as measured in Cleveland, Ohio on the first of the month for each month during the years 1971 – 2000. For example, \(t=3\) represents the average of the temperatures recorded for Lake Erie on every March 1 for the years 1971 – 2000.

Month
Number, \(t\) 1 2 3 4 5 6 7 8 9 10 11 12
Temperature
(\(^{\circ }\) F), \(T\) 36 33 34 38 47 57 67 74 73 67 56 46
  1. Using the techniques discussed in Example sinusoidsunlight, fit a sinusoid to these data.
  2. Graph your model along with the data set to judge the reasonableness of the fit.
  3. Use the model from LakeErieTempData to predict the average temperature recorded for Lake Erie on April \(15^{\text {th}}\) and September \(15^{\text {th}}\) during the years 1971–2000.
  4. Compare your results to those obtained using a graphing utility.
The fraction of the moon illuminated at midnight Eastern Standard Time on the \(t^{\text {th}}\) day of June, 2009 is given in the table below.

Day of
June, \(t\) 3 6 9 12 15 18 21 24 27 30
Fraction
Illuminated, \(F\) 0.81 0.98 0.98 0.83 0.57 0.27 0.04 0.03 0.26 0.58
  1. Using the techniques discussed in Example sinusoidsunlight, fit a sinusoid to these data.
  2. Graph your model along with the data set to judge the reasonableness of the fit.
  3. Use the model from MoonIllumination to predict the fraction of the moon illuminated on June 1, 2009.
  4. Compare your results to those obtained using a graphing utility.
Use a graphing utility to graph \(y = 8.36 \sin (-294.81t - 26.53) + 12.06\). (This is the regression model produced by desmos in Example sinusoidsunlight.) Zoom in, as needed, until you start to see the wave-like nature of the graph. Use Theorem sinusoidform to determine a window which produces exactly one complete cycle of this sinusoid and check your answer graphically.
Use Theorem transformationsthm to prove Theorem sinusoidform.
With the help of your classmates, research Amplitude Modulation and Frequency Modulation.
What other things in the world might be roughly sinusoidal? Look to see what models you can find for them and share your results with your class.