Find the range of \(f\). \(\answer {[-5,4]}\)
Find the maximum, if it exists.
\(f(-3) = 4\)
Find the minimum, if it exists.
\(f(-5) = -5\)
List the local maximums, if any exist.
\((-3,4)\), \((2,3)\)
List the local minimums, if any exist.
\((0,-1)\)
List the intervals where \(f\) is increasing.
\([-5,-3]\), \([0,2]\)
List the intervals where \(f\) is decreasing.
\([-3,0]\), \([2,3]\)
Determine \(f(-2)\). \(f(-2) = \answer {2}\)
Solve \(f(x) = 4\). \(x=\answer {-3}\)
List the \(x\)-intercepts, if any exist.
\((-4,0)\), \((-1,0)\), \((1,0)\)
List the \(y\)-intercepts, if any exist. \(\answer {(0,-1)}\)
Find the zeros of \(f\).
\(-4\), \(-1\), \(1\)
Solve \(f(x) \geq 0\).
\([-4,-1]\), \([1,3]\)
Find the number of solutions to \(f(x) = 1\). \(\answer {4}\)
Find the number of solutions to \(|f(x)| = 1\). \(\answer {6}\)
Solve \((x^2-x-2)f(x) = 0\)
\(x=-4, -1,1,2\)
Solve \((x^2-x-2)f(x) > 0\)
\((-4,-1) \cup (-1,1) \cup (2,3)\)
Find the domain of \(R(x) = \dfrac {1}{f(x)}\)
To find the domain of \(R(x) = \frac {1}{f(x)}\), we start with the domain of \(f\) and exclude values where \(f(x) = 0\). Hence, the domain of \(R\)
is \([-5,-4) \cup (-4,-1) \cup (-1,1) \cup (1,3]\).
Find the range of \(R(x) = \dfrac {1}{f(x)}\)
To find the range of \(R(x) = \frac {1}{f(x)}\), we start with the range of \(f\) (excluding \(0\)) and take reciprocals. If \(-5 \leq y < 0\), then \(\frac {1}{y} \leq -\frac {1}{5}\). If \(0 < y \leq 4\), then \(\frac {1}{y} \geq \frac {1}{4}\). Hence the range of \(R\) is \(\left (-\infty , -\frac {1}{5} \right ] \cup \left [ \frac {1}{4}, \infty \right )\).