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Use your calculator (You can do these without your calculator, but it may test your mettle!) to help you find the real
zeros of the polynomial. State the multiplicity of each real zero.
Use your calculator (You can do these without your calculator, but it may test your mettle!) to help you find the real
zeros of the polynomial. State the multiplicity of each real zero.
Use your calculator (You can do these without your calculator, but it may test your mettle!) to help you find the real
zeros of the polynomial. State the multiplicity of each real zero.
Find the real zeros of \(f(x) = x^{3} - \frac {1}{12}x^{2} - \frac {7}{72}x + \frac {1}{72}\) by first finding a polynomial \(q(x)\) with integer coefficients such that \(q(x) = N \cdot f(x)\) for some integer \(N\). (Recall that the
Rational Zeros Theorem required the polynomial in question to have integer coefficients.) Show that \(f\) and \(q\) have the same real
zeros.
We choose \(q(x) = 72x^{3} - 6x^{2} - 7x + 1 = 72 \cdot f(x)\). Clearly \(f(x) = 0\) if and only if \(q(x) = 0\) so they have the same real zeros. In this case, \(x = -\frac {1}{3}, \; x = \frac {1}{6} \;\) and \(x = \frac {1}{4}\) are the real zeros of both \(f\) and \(q\).
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(9x^{3} = 5x^{2} + x\)
\(x = 0, \frac {5\pm \sqrt {61}}{18}\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(9x^{2}+5x^{3}= 6x^{4}\)
\(x = 0, \frac {5 \pm \sqrt {241}}{12}\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(z^{3} + 6 = 2z^{2} + 5z\)
\(z = -2,1,3\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(z^{4} + 2z^{3} = 12z^{2} + 40z + 32\)
\(z=-2,4\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(t^{3} - 7t^{2} = 7-t\)
\(t=7\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(2t^{3} = 19t^{2} - 49t + 20\)
\(t = \frac {1}{2}, 4, 5\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(x^{3} + x^{2} = \frac {11x + 10}{3}\)
\(x = -2, \frac {3 \pm \sqrt {69}}{6}\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(x^4+2x^2 = 15\)
\(z = \pm \sqrt {3}\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(14z^{2}+5=3z^{4}\)
\(z = \pm \sqrt {5}\)
Find the real solutions of the polynomial equation. (See Example polyeqineqexample.)
\(2z^5+3z^4 = 18z + 27\)
\(z = -\frac {3}{2}, \pm \sqrt {3}\)
Solve the polynomial inequality and state your answer using interval notation. (Hint: type the word infinity to get the \(\infty \)
symbol.)
Use the the graph of the given polynomial function to solve the stated inequality.
Solve \(F(s) \leq 0\).
\(F(s) \leq 0\) on \(\{-2\} \cup [0, \infty )\)
Use the the graph of the given polynomial function to solve the stated inequality.
Solve \(G(t) \geq 0\).
\(G(t) \geq 0\) on \(\{-2\} \cup [0, \infty )\)
Use the Intermediate Value Theorem, Theorem IVT, to prove that \(f(x) = x^{3} - 9x + 5\) has a real zero in each of the following intervals: \([-4, -3], [0, 1]\) and
\([2, 3]\).
Since \(f(-4)=-23,\; f(-3)=5,\; f(0)=5,\; f(1)=-3,\; f(2)=-5\;\) and \(f(3)=5\) the Intermediate Value Theorem gives that \(f(x) = x^{3} - 9x + 5\) has real zeros in the intervals \([-4, -3], [0, 1]\) and \([2, 3]\).
Use the concepts of End Behavior and the Intermediate Value Theorem to prove any odd-degree polynomial function with
real number coefficients has at least one real zero.
An odd degree polynomial function \(f\) has ‘mismatched’ end behavior. That is, the end behavior of \(f(x)\) is either: \(\ds {\lim _{x \rightarrow -\infty } f(x) = -\infty }\) and \(\ds {\lim _{x \rightarrow \infty } f(x) = \infty }\) or \(\ds {\lim _{x \rightarrow -\infty } f(x) = \infty }\) and \(\ds {\lim _{x \rightarrow \infty } f(x) = -\infty }\).
This means at some point, \(f(x) > 0\) and at some other point \(f(x) < 0\). The Intermediate Value Theorem guarantees at least one place where \(f(x) = 0\).
Find an even-degree polynomial function with real number coefficients which has no real zeros.
The function \(f(x) = x^2+1\) has no real zeros.
Continue the Bisection Method as introduced on ?? to approximate the real zero of \(f(x) = x^5-x-1\) to three decimal places.
\(x \approx \answer {1.167}\).
In this exercise, we prove \(\sqrt {2}\) is an irrational number and approximate its value. Let \(f(x) = x^2-2\).
Use Decartes’ Rule of Signs to prove \(f\) has exactly one positive real zero.
\(f(x)\) has only one variation in sign, so the result follows from Descartes’ Rule of Signs.
Use the Intermediate Value Theorem to prove \(f\) has a zero in \([1,2]\).
\(f(1) = -1<0\) and \(f(2) = 2>0\) so the Intermediate Value Theorem promises a zero in \([1,2]\).
Use the Rational Zeros Theorem to prove \(f\) has no rational zeros.
The Rational Zeros Theorem gives the only possible rational zeros of \(f\) are \(\pm 1\) and \(\pm 2\). Since \(f(\pm 1) = -1\) and \(f(\pm 2) = 2\), \(f\) has no rational zeros.
Use the Bisection Method (see ??) to approximate the zero of \(f\) on \([1,2]\) to three decimal places.
If \(N\) is not the perfect square of an integer, then \(\sqrt {N}\) is irrational.
Consider \(f(x) = x^2-N\).
For natural numbers \(n \geq 2\), if \(N\) is not the perfect \(n^{\text {th}}\) power of an integer, then \(\sqrt [n]{N}\) is irrational.
Consider \(f(x) = x^n-N\).
In Example boxnotopex in Section GraphsofPolynomials, a box with no top is constructed from a \(10\) inch \(\times \) \(12\) inch piece of cardboard by cutting out congruent
squares from each corner of the cardboard and then folding the resulting tabs. We determined the volume of that box (in cubic
inches) is given by the function\(V(x) = 4x^3-44x^2+120x\), where \(x\) denotes the length of the side of the square which is removed from
each corner (in inches), \(0 < x < 5\). Solve the inequality \(V(x) \geq 80\) analytically and interpret your answer in the context of that
example.
\(V(x) \geq 80\) on \([1,5-\sqrt {5}] \cup [5+\sqrt {5}, \infty )\). Only the portion \([1,5-\sqrt {5}]\) lies in the applied domain, however. In the context of the problem, this says for the volume of the box
to be at least 80 cubic inches, the square removed from each corner needs to have a side length of at least 1 inch, but no
more than \(5-\sqrt {5} \approx 2.76\) inches.
From Exercise newportaboycost in Section GraphsofPolynomials, \(C(x) = .03x^{3} - 4.5x^{2} + 225x + 250\), for \(x \geq 0\) models the cost, in dollars, to produce \(x\) PortaBoy game systems. If the production budget is
\(\$5000\), find the number of game systems which can be produced and still remain under budget.
\(C(x) \leq 5000\) on (approximately) \((-\infty , 82.18]\). The portion of this which lies in the applied domain is \((0,82.18]\). Since \(x\) represents the number of game systems,
we check \(C(82) = 4983.04\) and \(C(83) = 5078.11\), so to remain within the production budget, anywhere between \(1\) and \(82\) game systems can be produced.
Let \(f(x) = 5x^{7} - 33x^{6} + 3x^{5} - 71x^{4} - 597x^{3} + 2097x^{2} - 1971x + 567\). With the help of your classmates, find the \(x\)- and \(y\)- intercepts of the graph of \(f\). Find the intervals on which the function is
increasing, the intervals on which it is decreasing and the local extrema. Sketch the graph of \(f\), using more than one picture if
necessary to show all of the important features of the graph.
With the help of your classmates, create a list of five polynomials with different degrees whose real zeros cannot be found
using any of the techniques in this section.